# Categoría: hayward escort

#### First, note that the smallest L2-norm vector that can fit the training data for the core model is $$>=[2,0,0]$$

First, note that the smallest L2-norm vector that can fit the training data for the core model is $$<\theta^\text>=[2,0,0]$$ On the other hand, in the presence of the spurious feature, the full model can fit the training data perfectly with a smaller norm by assigning weight $$1$$ for the feature $$s$$ ($$|<\theta^\text>|_2^2 = 4$$ while...